If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

Difficult Level - 5%.

# project euler 001 def main(): # declaration sum = 0 # input limit = 1000 # logic for x in range(1, limit): if (x % 5 == 0) or (x % 3 == 0): sum = sum + x # output print ("sum", sum) # calls main()